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If abc, bca and cab are three digit numbers, andabc + bca + cab = 3 × (a + b + c) × k, then the value of k will be:1. 332. 373. 1114. 11 |
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Answer» Correct Answer - Option 2 : 37 Concept used: Any number can be written as digit × place value For example:- 354 = 3 × 100 + 5 × 10 + 4 × 1 = 300 + 50 + 4 Solution: abc + bca + cab = 3 × (a + b + c) × k ⇒ (100a + 10b + c) + (100b + 10c + a) + (100c + 10a + b) = 3 × (a + b + c) × k ⇒ (100a + 10 a + a) + (100b + 10b + b) + (100c + 10c + c) = 3 × (a + b + c) × k ⇒ 111a + 111b + 111c = 3 × (a + b + c) × k ⇒ 111 × (a + b + c) = 3 × (a + b + c) × k ⇒ k = 111/3 ⇒ k = 37 |
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