1.

if AB*BA=BCB ehere a b c stand for one digit then calculate A+B+C=...? where Anot equal to B not equal to C. ​

Answer»

Finding place VALUES: ab*ba = bcb

(10a + b)* (10b + a) = 100b + 10c + b

100ab + 10(A2 + b2) + ab = 101b + 10c

101ab + 10(a2 + b2) = 101b + 10c

Equating like terms: When, a (b) = a(c), b = c

ab = b ; a = 1 assume b not equal 0.

a2 + b2 = c (substituting with value of a) BECOMES 12 + b2 = c

a +b + c (after substituting with values)

become 1 + b + 1 + b2 = 2 + b + b2

b = 1 and b=0 is not possible SINCE b is not equal to a.

For other values of b except 2 c is a double digit number which is not possible.

So b = 2 ; hence a + b + c = 2 + 2 + 4 =8

I hope I will help you please mark on berilent answer


Discussion

No Comment Found

Related InterviewSolutions