1.

If ab = 24, bc = 24, ac = 16 find :(i) a + b + c(ii) a² + b^2+ c^2+ 2(ab + bc + ac).

Answer»

ab=24, bc=24,AC= 16

or,a=24/b,c=24/b,a=16/c

comparing,

24/b=16/c

16c=24b

c=24b/16

=3b/2

again comparing,

3b/2=24/b

3b SQ.=48

b sq. =16

b=4

NEW SOLVE the other VALUE



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