1.

If a² = log x, b³ = log y and 3a² - 2b³ = 6 log z, express y in terms of x and z.If m = log 20 and n = log 25, find the value of x, so that : 2 log ( x - 4 ) = 2 m - n.

Answer»

3a² - 2b³ = 6 LOG z
⇒ 3 log X - 2 log y = 6 log z
⇒ log x³ - log y² = log z⁶
⇒ log (x³/y²) = log z⁶
⇒ x³/y² = z⁶
⇒ y² = z⁶/x³
⇒ y = \sqrt{\frac{z^6}{x^3} }= \frac{z^3}{x^{ 1.5}}


Discussion

No Comment Found

Related InterviewSolutions