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If a^x=b^y=c^z and y=(xz)^1/2 , find the value of loga*logc/(logb)^2 |
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Answer» a^x=b^y=c^z apply log on all SIDES and let it EQUALS to k HENCE , xloga=ylogb=zlogc=k loga=k/x, logb=k/y, logc=k/z substitute in loga*logc/(logb)^2 ((k/x)*(k/z)) / (k^2/y^2) CANCEL k^2 then, y^2/x*z but its given that it equals 1 hence, loga*logc/(logb)^2 = 1 |
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