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If `A=[(x,1),(1,0)] and A=A^(-1)`, then x= . . . . |
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Answer» Correct Answer - A We have, A=`[[x,1],[1,0]]` `absA=("x"xx0-1)=-1` adj A=`[[0,-1],[-1.x]]` `A^(-1)=(adjA)/(absA)=(-1)[[0,-1],[-1,x]]=[[0,1],[1,-x]]` Since, it is given, A=`A^(-1)` `rArr[[x,1],[1,0]]=[[0,1],[1,-x]]` `rArrx=0` {By equality of matrices} |
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