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If a vertex of an equilateral triangle is the origin and the side opposite to it has the equation x+y=1, then orthocentre of the triangle is : |
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Answer» `ax+by+c=0` `(x1,y1)` `(x-x1)/a=(y-y1)/b=-(ax1+by1+c)/(a^2+b^2)` `x/1=y/1=-(-1)/(1^2+1^2)` `x=1/2,y=1/2` `G=(((2xx1/2+1xx0)/(2+1),2xx1/2+1xx0)/(2+1))` `G=(1/3,1/3)` |
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