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If a vehicle starts from rest and moves with a uniform acceleration of 10meters per seconds square for 10 seconds, determine the distance covered in the last second of the motion |
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Answer» Given that, Acceleration (a) = 10m/s² Time (t) = 10 sec. Initial VELOCITY (u) = 0m/s² (as the vehicle is starting from rest.) To find, The distance travelled in the last seconds = ? From the SECOND equation of motion, s = ut + 1/2 at² s = 0 * 10 + 1/2 * 10 * 10 * 10 s = 0 + 1/2 * 1000 s = 1/2 + 1000 s = 500mTherefore, the distance travelled in the last seconds is 500M. |
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