1.

if a vector = 2 i cap - 2 j cap -k cap and b = icap + j cap then find angle between a vector and b vector.​

Answer»

Given:-

a vec. = 2i^ -2j^-k^

and

B vec. =i^+j^

To find:-

Angle between TWO vectors. vector "a" and ''b ".

Solution:-

To find the vector between two angles, knowing dot product is very necessary!!

\\ so \: \: \\ a.b = \cos(x) |a| |b|

hence. \\ \\ \: \cos(x) = \frac{a.b}{ |a| |b| }

here, x is the angle between two Vectors,.

Now,

\cos(x) = \frac{(2i - 2j - k)(i + j)}{ \sqrt{(4 + 4 + 1) \sqrt{1 + 1} } }

Now,

as we know i^.j^=0 ,and i^.i^=1.

=> cos(x)= (2-2)/√18= 0/3√2

=>cos(x)=0

so, (x)=90°

So,the angle inclined is 90° .

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