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If a variable force f=2x is applied, what will be the work done in moving the particle from x=10 to 0?Need solution without integration |
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Answer» Work done = \(\int\limits_{10}^0fdx\) = \(\int\limits_{10}^02xdx\) = \([x^2]_{10}^0\) = 02 - 102 = -100 |
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