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If a solid sphere of radius r is melted and cast into the shape of a solid cone of height r, then the radius of the base of the cone is : A. 2r B. 3r C. r D. 4r |
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Answer» Option : (A) Volume of a sphere = \(\frac{4}{3}\)πr3 Volume of a solid cone = \(\frac{1}{3}\)πr2h Given, solid sphere of radius r is melted and cast into the shape of a solid cone of height r Let the base radius be A. ⇒ \(\frac{4}{3}\)πr3 = \(\frac{1}{3}\)π × A2 × r ⇒ A = 2r |
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