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If a solid right circular cylinder made of iron is heated to increase its radius and height by 1% each, then by how much per cent is the volume of the solid increased? |
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Answer» Let r and h be the radius and height of the cylinder respectively. Then, after 1% increase, New radius = 1.1 r and new height = 1.1 h Original volume = πr2h , New volume = π(1.01r)2 (1.01h) =1.030301 πr2h ∴ % increase = \(\bigg(\frac{1.030301πr^2h-πr^2h}{πr^h}\times100\bigg)\)% = \(\bigg(\frac{0.030301πr^2h}{πr^h}\times100\bigg)\)% = (0.030301 × 100)% = 3.03% Volume of solid cylinder V= πr2h If initial radius and height are 100cm each then increased radius and height will be 101cm each. Initial volume V1=π×100×1002 Increased volume V2= π×101×1012 Percentage increase =[ (V2-V1)/V1]×100 =(101^3-100^3)/100^3×100 = 3.0301% |
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