1.

If a solid right circular cylinder made of iron is heated to increase its radius and height by 1% each, then by how much per cent is the volume of the solid increased?

Answer»

Let r and h be the radius and height of the cylinder respectively. Then, after 1% increase, 

New radius = 1.1 r and new height = 1.1 h 

Original volume = πr2h , 

New volume = π(1.01r)2 (1.01h) =1.030301 πr2h

∴ % increase = \(\bigg(\frac{1.030301πr^2h-πr^2h}{πr^h}\times100\bigg)\)% = \(\bigg(\frac{0.030301πr^2h}{πr^h}\times100\bigg)\)%

= (0.030301 × 100)% = 3.03%

Volume of solid cylinder V= πr2h

If initial radius and height are 100cm each then increased radius and height will be 101cm each.

Initial volume V1=π×100×1002

Increased volume V2= π×101×1012

Percentage increase 

=[ (V2-V1)/V1]×100

=(101^3-100^3)/100^3×100

= 3.0301%



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