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If a scooterist drives at the rate of 24 km/hr from his1.place 5 minutes late. But if he drives at the rate of 30place 4 minutes early(a) Find the distance of his work place from his home. |
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Answer» Assume that he starts travelling to his workplace at the same time every day Let the distance between his work place and home be 'd' Let the actual time be 'x' Distance = Speed * Time Convert minutes into seconds as the units should be in kmph As 24 kmph speed resulted in 5 minutes late, it is taken as increment d = 24(x + 5/60) ---------------(1) As 30 kmph speed resulted in 4 minutes early, it is taken as decrement d = 30(x - 4/60) ----------------(2) (1) and (2) are equal => 24(x + 5/60) = 30(x - 4/60)=> 24x+2 = 30x-2=> 30x - 24x = 2+2=> 6x = 4=> x = 2/3 Substitute the value of x in (1)=> d = 24(2/3 + 5/60)=> d = 24(9/12)=> d = 18 km The required answer is 18 km |
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