If a radioactive material is decayed by 20% in aminute. Then its half

1.	If a radioactive material is decayed by 20% in aminute. Then its half period will be(1) 80.6 sec(2) 1863 -(3) 100.3 sec14) 206 3 sec
Answer» Answer: N = N0 E^-ct N / N0 = .8 = e^-c where t = 1 min (c has units of 1 / min) LN .8 = -c c = .223 N / N0 = 1/2 = e^(-t* .223) ln .5 = -.223 t t = .693 / .223 = 3.11 min = 186.6 sec

If a radioactive material is decayed by 20% in aminute. Then its half period will be(1) 80.6 sec(2) 1863 -(3) 100.3 sec14) 206 3 sec

Answer»

Answer:

N = N0 E^-ct

N / N0 = .8 = e^-c where t = 1 min (c has units of 1 / min)

LN .8 = -c

c = .223

N / N0 = 1/2 = e^(-t* .223)

ln .5 = -.223 t

t = .693 / .223 = 3.11 min = 186.6 sec

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If a radioactive material is decayed by 20% in aminute. Then its half period will be(1) 80.6 sec(2) 1863 -(3) 100.3 sec14) 206 3 sec​

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If a radioactive material is decayed by 20% in aminute. Then its half period will be(1) 80.6 sec(2) 1863 -(3) 100.3 sec14) 206 3 sec