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If a polynomial p(x)=x²+12x+27 is divisible by (x+a) then find the value of a.. |
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Answer» p(X)=x^2+12x+27 x+a=0 x= -a p(-a)=(-a)^2+12(a)+27=0 p(-a)=a+12a+27=0 p(-a)=13a+27=0 13a=-27 a= -27/13 a= -2.07 |
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