If a pole hm high casts a shadow √3/3 h meter long on the ground fin

1.	If a pole hm high casts a shadow √3/3 h meter long on the ground find the sun's elevation?
Answer» Solution :- LENGTH of the POLE = H meters Length of the shadow = (√3/3 ) * h meters Let θ be the angle of SUN's elevation The ratio of length of pole and shadow is TAN θ ⇒ tanθ = Lengths of the pole / Length of the shadow $\implies \tan \theta = \dfrac{h}{ \dfrac{ \sqrt{3} }{3}h}$ $\implies \tan \theta = \dfrac{1}{ \dfrac{ \sqrt{3} }{3}}$ $\implies \tan \theta =1 \times \dfrac{3}{ \sqrt{3} }$ $\implies \tan \theta = \dfrac{3}{ \sqrt{3} }$ $\implies \tan \theta = \sqrt{3}$ $\implies \tan \theta = \tan60$ [ Because tan60 = √3 ] $\implies \theta = 60$ Therefore 60° is the angle of sun's elevation.