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If a particle rotates along a circle of radius 3 m with an angular acceleration of `(pi)/(2) "rad"//s^(2)` starting from rest, then its average velocity over the time it covers quarter circle is :A. `1 m//s`B. `2 m//s`C. `3 m//s`D. `4 m//s` |
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Answer» Correct Answer - C `theta = omega_(0) t + (1)/(2) alpha t^(2)` `(pi)/(2) = 0 + (1)/(2) (pi)/(2) t^(2)` `t = sqrt2` average `v = (s)/(t) = (R sqrt2)/(sqrt2) = R = 3 ms^(-1)` |
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