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If a particle of mass m start from along curved circular path shown in figure with constant tangential acceleration a, then net force at B on the particle has the magnitude : A. zeroB. `2ma sqrt(1 + pi^(2))`C. `ma sqrt(1 + pi^(2))`D. `ma pi sqrt(1 + pi)` |
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Answer» Correct Answer - C `F_("net") = ma_("total") = m sqrt(a_(t)^(a) + a_(c )^(2))` `a_(t) = a` `a_(c ) = (v^(2))/(R )` `v^(2) = 0 + 2a ((pi R)/(2))` `u = sqrt(pi R a) " " rArr a_(c ) = (pi R a)/(R ) = pi a` |
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