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if a particle is thrown upward with a speed of 75m/sec find the distance traveled by particle in 8th second |
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Answer» 2.5 mExplanation:Method Normal .Note there is a direction CHANGE when ball attains maximum height .The time taken by ball to get to MAX height can be found this WAY : v = u - gt 0 = 75 - 10T t = 7.5 seconds. H = 75*75/20 = 281.25 m Distance travelled in 8th second = Distance travelled in 8 seconds - Distance travelled in 7 seconds So, distance travelled in 0.5 s = 5(0.5)^2 = 1.25 mDistance travelled in 7 seconds =75(7)-5(49)= 35(15-7) = 8*35 = 280So , S8 - S7 = (281.25+1.25-280) = 2.5 m |
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