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If a\operatorname{sinθ+\operatorname{cosθ=c, then prove that a\operatorname{cosθ-b\operatorname{sinθ=\sqrt{a^2+b^2-c^2

Answer» If a\operatorname{sinθ+\operatorname{cosθ=c, then prove that a\operatorname{cosθ-b\operatorname{sinθ=\sqrt{a^2+b^2-c^2


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