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If a\operatorname{cosθ-b\operatorname{sinθ=c, then a\operatorname{sinθ+b\operatorname{cosθ={(a)\pm\sqrt{a^2+b^2+c^2{(b)\pm\sqrt{c^2-a^2-b^2 (c)\sqrt{a^2+b^2-c^{

Answer» If a\operatorname{cosθ-b\operatorname{sinθ=c, then a\operatorname{sinθ+b\operatorname{cosθ={(a)\pm\sqrt{a^2+b^2+c^2{(b)\pm\sqrt{c^2-a^2-b^2 (c)\sqrt{a^2+b^2-c^{


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