1.

If a number N can be represented as Pa1×Pb2×Pc3 where P1,P2,P3 are prime factors of N then number of factors of N can be found as (a+1)×(b+1)×(c+1)

Answer» If a number N can be represented as Pa1×Pb2×Pc3 where P1,P2,P3 are prime factors of N then number of factors of N can be found as (a+1)×(b+1)×(c+1)


Discussion

No Comment Found

Related InterviewSolutions