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If a normal makes an angle θ with positive x-axis then the slope of the curve at the point where the normal is drawn is …(a) – cot θ (b) tan θ (c) – tan θ (d) cot θ |
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Answer» (a) – cot θ Given, the slope of normal = -1/m = tan θ Slope of the tangent = m = - 1/tan θ = - cot θ |
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