If a kite is flying at a height of 40√3m from the level ground, atta

1.	If a kite is flying at a height of 40√3m from the level ground, attached to a string inclined at 60 degree to the horizontal, then the length of the string is
Answer» ONG>ANSWER: $\setlength{\unitlength}{25} \begin{picture}(5,5) \linethickness{1}\put(1,1){\line(1,0){3}} \put(4,1){\line(0,1){4}}\qbezier(1,1)(1,1)(4,5)\qbezier(1.7,1)(1.7,1.4)(1.5,1.6)\put(3.7,1){\line(0,1){0.3}}\put(3.7,1.3){\line(1,0){0.3}}\put(3.9,5.1){$ \bf C$}\put(3.9,0.5){$ \bf B$}\put(0.8,0.5){$ \bf A $}\put(1.8,1.25){$ \bf {60}^{ \circ} $}\put(4.2,3){$ \bf 40 \sqrt{3}\: m$}\put(1.7,3){$ \bf x $}\end{picture}$ ━━━━━━━━━━━━━━━━━━━━━━━━━━ Here, $\;\;\;\bullet\;\;$ HEIGHT of KITE from ground is 40√3 m. $\;\;\;\bullet\;\;$ Let Height of STRING attached with kite be x. $\;\;\;\bullet\;\;$ Angle of ELEVATION = 60° $\\$ ★ In ∆ABC, $\\$ $\star\;\sf sin\;60^\circ = \dfrac{BC}{AC} = \dfrac{P}{H}\\ \\$ $:\implies\sf \dfrac{ \sqrt{3}}{2} = \dfrac{40\sqrt{3}}{x}\\ \\$ $:\implies\sf \sqrt{3} x = 40 \sqrt{3} \times 2\\ \\$ $:\implies\sf \sqrt{3} x = 80 \sqrt{3}\\ \\$ $:\implies\sf x = \dfrac{80 \cancel{\sqrt{3}}}{ \cancel{ \sqrt{3}}}\\ \\$ $:\implies{\underline{\boxed{\sf{\pink{x = 80\;m}}}}}\;\bigstar\\ \\$ $\therefore\; {\underline{\sf{Hence,\;the\; length\;of\;string\;is\; \bf{100\;m}}}}$

If a kite is flying at a height of 40√3m from the level ground, attached to a string inclined at 60 degree to the horizontal, then the length of the string is

Answer» ONG>ANSWER:

$\setlength{\unitlength}{25} \begin{picture}(5,5) \linethickness{1}\put(1,1){\line(1,0){3}} \put(4,1){\line(0,1){4}}\qbezier(1,1)(1,1)(4,5)\qbezier(1.7,1)(1.7,1.4)(1.5,1.6)\put(3.7,1){\line(0,1){0.3}}\put(3.7,1.3){\line(1,0){0.3}}\put(3.9,5.1){$ \bf C$}\put(3.9,0.5){$ \bf B$}\put(0.8,0.5){$ \bf A $}\put(1.8,1.25){$ \bf {60}^{ \circ} $}\put(4.2,3){$ \bf 40 \sqrt{3}\: m$}\put(1.7,3){$ \bf x $}\end{picture}$