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If →a=^i+^j−2^k, then ∣∣(→a×^i)×^j∣∣2+∣∣(→a×^j)×^k∣∣2+∣∣(→a×^k)×^i∣∣2= |
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Answer» If →a=^i+^j−2^k, then ∣∣(→a×^i)×^j∣∣2+∣∣(→a×^j)×^k∣∣2+∣∣(→a×^k)×^i∣∣2= |
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