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If →a=^i+^j−2^k, then ∣∣(→a×^i)×^j∣∣2+∣∣(→a×^j)×^k∣∣2+∣∣(→a×^k)×^i∣∣2=

Answer» If a=^i+^j2^k, then (a×^i)×^j2+(a×^j)×^k2+(a×^k)×^i2=


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