1.

If a force of 50N is applied to the bodyon the right side while a force of 20N is applied tothe body on the left side and initially body is at rest.What is the behaviour of the motion of the body?

Answer»

Explanation:

Retarding force, F=50N

Mass of the body, m=20kg

Initial velocity of the body, u=15m/s

Final velocity of the body, v=0

Using NEWTONS second LAW of motion, the acceleration (a) PRODUCED is given by:

F=ma

50=20 ×a

a=−50/20=−2.5m/s

2

Using the FIRST equation of motion, the time (t) taken by the body to come at rest

v=u+at

t=−u/a=−15/−2.5=6s



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