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If a force of 50N is applied to the bodyon the right side while a force of 20N is applied tothe body on the left side and initially body is at rest.What is the behaviour of the motion of the body? |
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Answer» Explanation: Retarding force, F=50N Mass of the body, m=20kg Initial velocity of the body, u=15m/s Final velocity of the body, v=0 Using NEWTONS second LAW of motion, the acceleration (a) PRODUCED is given by: F=ma 50=20 ×a a=−50/20=−2.5m/s 2
Using the FIRST equation of motion, the time (t) taken by the body to come at rest v=u+at t=−u/a=−15/−2.5=6s |
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