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If a diameter AB of a circle with centre O bisects each of the two chords CD and EF as shownin the figure, Prove that the two chords are parallel. |
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Answer» Given Diameter AB bisect chords CD and EF , So CM = MDAndEN = NF And we know a line from center to chord is bisect that chord than that line also perpendicular on that chord . So OM⊥CD and ON⊥EFSo,∠OMC =∠OMD =∠ONE =∠ONF = 90° And∠OMC +∠ ONE = 180° ------ ( 1 ) These are consecutive interior angles , Only satisfied equation 1 true if CD | | EF , Where MN is transversal line .So,CD | | EF ( Hence proved ) |
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