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If a current of 1 amp is flowing through a wire, then how many electrons are flowing per sec. A given cross-section of the wire?\[\left[6.25 \times 10^{18}\right. \text { electrons/sec] }\] |
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Answer» q = it q = 1 x 1 q = 1c q = 1 e n = q/2 n = \(\frac{1}{1.6\times10^{-19}}\) ⇒ 0.625 x 1019 e/sec |
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