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if a,b,y are the zeroes of the polynomial p (x)= 6x^3-3x^2-5x+1, find the value of 1/a+1/b+1/y |
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Answer» Given that a, b, y are zeros of polynomial p(x) = 6x3 - 3x2 - 5x + 1 \(\therefore\) Product of zeros = -d/a = -1/6 Sum of product of two zeros = c/a = -5/6 Sum of zeros = -b/a = \(\frac{-(-3)}{6}\) = 3/6 = 1/2 \(\because\) 1/a + 1/b + 1/y = \(\frac{by+ay+ab}{aby}\) = \(\frac{sum\,of\,product\,of\,two\,zeros}{product\,of\,zeros}\) \(=\cfrac{\frac{-5}{6}}{\frac{-1}6}\) = 5 |
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