1.

If a=b^x,b=c^y and c=a^z then find the value of xyz

Answer»

A=B^x
by taking log we get,
log a= log(b^x) {as, log (m^n)=n log m}
=x log b
or, x= (log a)/ (log b)

similarly, y=(log b)/(log c)
and Z= (log c)/(log a)

thus,
XYZ
=(log a× log b× log c)÷(log a×log b× log c)
=1


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