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If a : b = c : d = e : f, then (pa +qc + re) : (pb +qd + rf) is equal to(a) p : (q + r) (b) (p + q) : r (c) 2 : 3 (d) 1 : 2 |
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Answer» (d) 1 : 2 Given, \(\frac{a}{b}\) = \(\frac{c}{d}\) = \(\frac{e}{f}\)= \(\frac12\) So, let a = c = e = x and b = d = f = 2x ∴ \(\frac{(pa+qc+re)}{(pb+qd+rf)}\) = \(\frac{p\times{x}+q\times{x}+r\times{x}}{p\times2x+q\times2x+r\times2x}\) = \(\frac{x(p+q+r)}{2x(p+q+r)} =\frac12\) |
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