1.

if A B C are a right angle trianglewhere C is hypotenuseprove that radius r of the circle which touches the side of the triangleis given by R= A+ B+ C/2​

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ANSWER:

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Step-by-step explanation:

Let the CIRCLE touches sides AB,BC and CA at F,D and E RESPECTIVELY where AB=c,BS=a and AC=b

Length of the tangents drawn from an external point are equal.

AE=AF  

BD=BF

CE=CD=r

b−r=AF

a−r=BF

So, AB=AF+BF

c=b−r+a−r

c=a+b−2r

2r=a+b−c

r=2a+b−c



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