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If a+b+c=2s, then find the value of (s-a)^3+(s-b)^3+3(s-a)(s-b)c |
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Answer» Answer: a=2 b=2 c=2 then Step-by-step EXPLANATION: (s-2)^3+ (s-2)^3+3(s-2)(s-2)2 now CANCEL all the s so remains 2×3 + 2×3+3,+2+2+2 6+9+6 Ans is 21. |
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