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If A + B + C = 180, then tan (A + B/2) = _____. |
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Answer» ong>Answer: According to the question we know that A+B+C =180 So, => A+B=180-C Let MULTIPLY by TAN we FOUND that => tan(A+B) = tan(180-C) (TANA + tanb)/(1 - tana \: tanb)} = - tanc => tanA+tanB = -tanC(1-tanA tanB) => tanA+tanB= - tanC+tanA tanB tanC => tanA +tanB +tanC = tanA tanB tanC Hence proved |
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