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If a(b+c)=119, b(c+a)=128, c(a+b)=128, then find the value of abc​

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answers: If `alpha=pi/(15),\ ` then the VALUE of `prod_(r=1)^7cos ralpha` is- a.`1/(128)` B. `1/(128)` C.`1/(64)` d. `1/(32)`



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