If a+b+c=0 then prove that the roots of (b+c-a)x²+(c+a+b)x+(a+b-c)=0

1.	If a+b+c=0 then prove that the roots of (b+c-a)x²+(c+a+b)x+(a+b-c)=0 are real numbers
Answer» Step-by-step EXPLANATION: a+b+c=0 b+c=a (b+c-a) $<klux>X</klux>^{2}$ +(c+a+b)x+(a+b+c)=(a-a) $x^{2}$ +0+0 =0

If a+b+c=0 then prove that the roots of (b+c-a)x²+(c+a+b)x+(a+b-c)=0 are real numbers

Answer»

Step-by-step EXPLANATION:

a+b+c=0

b+c=a

(b+c-a) $<klux>X</klux>^{2}$ +(c+a+b)x+(a+b+c)=(a-a) $x^{2}$ +0+0

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If a+b+c=0 then prove that the roots of (b+c-a)x²+(c+a+b)x+(a+b-c)=0 are real numbers

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