1.

If a+b+c=0 then prove that a³+b³+c³=3abc​

Answer»

ANSWER:-

We KNOW,

a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² - ab - bc - CA)

Given that: (a + b + c) = 0.

Putting the value:-

a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² - ab - bc - ca)

→ a³ + b³ + c³ - 3abc = (0)(a² + b² + c² - ab - bc - ca)

→ a³ + b³ + c³ - 3abc = 0

a³ + b³ + c³ = 3abc

HENCE, Proved.



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