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If a+b+c=0 then prove that a³+b³+c³=3abc |
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Answer» ANSWER:- We KNOW, a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² - ab - bc - CA) Given that: (a + b + c) = 0. Putting the value:- a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² - ab - bc - ca) → a³ + b³ + c³ - 3abc = (0)(a² + b² + c² - ab - bc - ca) → a³ + b³ + c³ - 3abc = 0 → a³ + b³ + c³ = 3abc HENCE, Proved. |
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