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If a + b + c = 0, then a3 + b3 + c3 is equal to (A) 0 (B) abc (C) 3abc (D) 2abc |
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Answer» (c) 3abc Now, a3+b3 + c3 = (a+ b + c) (a2 + b2 + c2 – ab – be – ca) + 3abc = 0 + 3abc [∴ a + b + c = 0, given] a3+b3 + c3 = 3abc |
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