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If a + b + c = 0 and ∣∣∣∣a−xcbcb−xabac−x∣∣∣∣=0 then show that x = 0, x=√32(a2+b2+c2) |
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Answer» If a + b + c = 0 and ∣∣ ∣∣a−xcbcb−xabac−x∣∣ ∣∣=0 then show that x = 0, x=√32(a2+b2+c2) |
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