If a/b=b/c then solve (a²+ b²+2ab)/(b² +c²+2bc)= a/c.My question w

1.	If a/b=b/c then solve (a²+ b²+2ab)/(b² +c²+2bc)= a/c.My question was wrong last time now it is correct please show step by step .
Answer» $\huge\underline\bold\red{Answer:}$ HENCE Proved $\huge\underline\bold\red{Proof:}$ $\frac{a}{<klux>B</klux>} = \frac{b}{c}$ ${b}^{2} = ac$ $b = \sqrt{ac}$ $LHS = \frac{ (a²+ b²+2ab) }{(b² +c²+2bc)}$ Applying the VALUE of b² and b $= \frac{ {a}^{2} + ac + 2a \sqrt{ac} }{ac + {c}^{2} + 2c \sqrt{ac} }$ $= \frac{a(a + c + 2 \sqrt{ac}) }{c(a + c + 2 \sqrt{ac}) }$ $= \frac{a}{c}$ $=RHS$