If A B And C are angles of a triangle then show that sin(A+B)= sinC

1.	If A B And C are angles of a triangle then show that sin(A+B)= sinC
Answer» Step-by-step EXPLANATION: A, B *and* C *are* *the* *angles* of a *TRIANGLE. Then, <A+<B+<C=180°(Angle Sum* *property) =><A+<B=180°-<C =>Sin(<A+<B) =Sin(180°-<C) {Taking* *sin* on *both* *sides) =>Sin(A+B) =SinC* (*Sin(180°-theta=Sin THETA). Hence* *PROVED*........

Answer»

Step-by-step EXPLANATION:

A, B and C are the angles of a TRIANGLE.

Then,

<A+<B+<C=180°(Angle Sum property)

=><A+<B=180°-<C

=>Sin(<A+<B) =Sin(180°-<C) {Taking sin on both sides)

=>Sin(A+B) =SinC (Sin(180°-theta=Sin THETA).

Hence PROVED........

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If A B And C are angles of a triangle then show that sin(A+B)= sinC

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