1.

If A + B = 90°, then what is the value of \(\sqrt{\text{sin A sec B - sin A cos B}}\,?\)

Answer»

Given A + B = 90°

∴ \(\sqrt{\text{sin A sec B - sin A cos B}}\)

\(\sqrt{\text{sin A sec (90°- A) - sin A cos (90° - A)}}\)

\(\sqrt{\text{sin A cosec A - sin A. sin A}}\) 

\(\sqrt{1-sin^2 A}\) = \(\sqrt{cos^2 A}\) = cos A.



Discussion

No Comment Found