Saved Bookmarks
| 1. |
If A + B = 90°, then what is the value of \(\sqrt{\text{sin A sec B - sin A cos B}}\,?\) |
|
Answer» Given A + B = 90° ∴ \(\sqrt{\text{sin A sec B - sin A cos B}}\) = \(\sqrt{\text{sin A sec (90°- A) - sin A cos (90° - A)}}\) = \(\sqrt{\text{sin A cosec A - sin A. sin A}}\) = \(\sqrt{1-sin^2 A}\) = \(\sqrt{cos^2 A}\) = cos A. |
|