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If A + B = 90°, then tan A tan B+tan A cot Bsin A sec B-sin2 Bcos2 A is equal to(a) cot2 A(b) cot2 B(c) −tan2 A(d) −cot2 A |
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Answer» If A + B = 90°, then is equal to (a) cot2 A (b) cot2 B (c) −tan2 A (d) −cot2 A |
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