1.

If A + B = 90°, then tan A tan B+tan A cot Bsin A sec B-sin2 Bcos2 A is equal to(a) cot2 A(b) cot2 B(c) −tan2 A(d) −cot2 A

Answer» If A + B = 90°, then tan A tan B+tan A cot Bsin A sec B-sin2 Bcos2 A is equal to



(a) cot2 A

(b) cot2 B

(c) −tan2 A

(d) −cot2 A


Discussion

No Comment Found

Related InterviewSolutions