1.

If (a-b)2+ (b-c)2 + (c-d)2 + (d-5)² = 0then the valuea+b+c=​

Answer»

ANSWER:

(a−5)2=0⟹a=5  

(b−c)2=0⟹b=c

(c−d)2=0⟹c=d⟹b=c=d

(b+c+d−9)2=0⟹b+c+d=9⟹3b=3c=3d=9⟹b=c=d=3

(a+b+c)∗(b+c+d)=(5+3+3)∗(3+3+3)=11∗9=99

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