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If (a-b)=2 , a^3-b^3 = 26 then (a+b)^2=? |
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Answer» = Step-by-step EXPLANATION: given (a-b)=2 squaring on both sides a^2+b^2-2ab=4 a^2+b^2=4+2ab--(1) (a^3-b^3)=26 (a-b)(a^2+ab+b^2)=26 a^2+ab+b^2=26/2=13 4+3ab=13 3ab=9 ab=3--(2) (2) substitute in (1) so a^2+b^2=4+6=10 but a+b)^2=a^2+b^2+2ab=10+6=16 a+b=4 |
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