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If ∠A and ∠P are acute angle such that tan A = tan p, then show that ∠A = ∠P. |
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Answer» In a right angled triangle APQ, tan A = \(\frac{PQ}{AQ}\) and tan P = \(\frac{AQ}{PQ}\) ∵ tan A = tan P \(\frac{PQ}{AQ} = \frac{AQ}{PQ}\) ∵ PQ = AQ ∠P = ∠A = 45° |
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