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If α and β are zeroes of the quadratic polynomial p(x)=x2-(k-6)x+(2k+1) and α+β= αβ, then find the value of k |
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Answer» HIII friend, P(X) = X²-(K-6)+X+(2K+1). A = 1 , B = (K-6) and C = 2K+1 Alpha + BETA = -B/A = -(K-6)/1 And, Alpha × Beta = C/A =2K+1/1 According to question, Alpha + Beta = Alpha × Beta (K-6) = 2K+1 K-6 = 2K+1 2K-K =-6-1 K = -7 Hence, K = -7 HOPE IT WILL HELP YOU.... :-) |
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