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If A and B are two independent events such that P(A ∪ B) = 0.6, P(A) = 0.2, find P(B). |
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Answer» Given A and B are independent. ⇒ P(A ∪ B) = P(A).P(B) Here P(A ∪ B) = 0.6 and P(A) = 0.2 To find P(B): Now, P(A ∪ B) = P(A) + P(B) – P(A ∩ B) (i.e.,) P(A ∪ B) = P(A) + P(B) – P(A) . P(B) (i.e.,) 0.6 = 0.2 + P(B) (1 – 0.2) P(B) (0.8) = 0.4 ⇒ P(B) = 0.4/0.8 = 4/8 = 1/2 = 0.5. |
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