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If A and B are events such that P(A) = 0.42, P(B)=0.48, P(A and B) = 0.16 determine (i) P (not A) (ii) P (not B) (iii) P (A or B). |
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Answer» P(A) = 0.42 P(8) = 0.48, P(A ∩B) = 0.16 (i) P(A1) = 1 - 0.42 = 0.58 (ii) P(B1) = 1 - 0.48 = 0.52 (iii) P(A ∪ B) = P(A) + P(B) - P(A ∩ B) = 0.42 + 0.48 - 0.16 = 0.50 - 0.16 = 0.74. |
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