1.

If A = {a, b, c}, then number of possible non-zero relations in A is(A) 511(B) 512(C) 8(D) 7

Answer»

Answer is  (A)

A = {a, b, c} 

Number of elements in A = n(A) = 3

Then, numbers of elements in A × A 

= n(A × A) = 32 = 9

So, the number of relations in A are 

= 2n – 1 = 29 – 1 

= 512 – 1 = 511.



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