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If A = {a, b, c}, then number of possible non-zero relations in A is(A) 511(B) 512(C) 8(D) 7 |
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Answer» Answer is (A) A = {a, b, c} Number of elements in A = n(A) = 3 Then, numbers of elements in A × A = n(A × A) = 32 = 9 So, the number of relations in A are = 2n – 1 = 29 – 1 = 512 – 1 = 511. |
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